Answer
The increase in the kinetic energy of the block is $~~34.4~J$
Work Step by Step
We can find the work done by the applied force:
$W = (35.0~N)(3.00~m) = 105~J$
We can find the work done by the friction force:
$W = -(4.00~kg)(9.80~m/s^2)(3.00~m)(0.600) = -70.6~J$
We can find the net work done on the block:
$W_{net} = 105~J-70.6~J = 34.4~J$
The increase in the kinetic energy of the block is $~~34.4~J$
