Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 41 - Conduction of Electricity in Solids - Problems - Page 1273: 9d

Answer

$\lambda = 5.22 \times 10^{-10}m$

Work Step by Step

$\lambda = \frac{h}{mv_F}$ Where $h = 6.626\times 10^{-34} J.s$ $m=9.109\times 10^{-31} kg$ $v_F = 1.39 \times 10^{6} m/s$ $\lambda = \frac{6.626\times 10^{-34} J.s}{(9.109\times 10^{-31} kg)(1.39 \times 10^{6} m/s)}$ $\lambda = 5.22 \times 10^{-10}m$
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