Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 41 - Conduction of Electricity in Solids - Problems - Page 1273: 5b

Answer

$C = 6.81\times 10^{27} m^{-3}.eV^{-3/2}$

Work Step by Step

From the previous answer we got $C = 1.062 \times 10^{56} kg^{3/2}/J^3.s^3$ The unit 1 J = 1 $kg.m^2/s^2$ this means 1 $kg$ = 1 $J.s^2/m^2$ So units can be written $(J.s^2) ^{3/2}.m^{(-3)(3/2)}.J^{-3}.s^{-3}$ Simplify $J^{-3/2}.m{-3}$ Also remember that $e= 1.602 \times 10^{-19} J/eV$ Hence $C = (1.062 \times 10^{56} J^{-3/2}.m{-3}) ( 1.602 \times 10^{-19} J/eV) $ $C = 6.81\times 10^{27} m^{-3}.eV^{-3/2}$
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