Answer
$P = 9\times10^{-43} \approx 10^{-42}$
Work Step by Step
The probability is given by
$P = N_0^{-E_g/kT}$
Where $N_0 = (M_e/m)NA$
$P = \frac{M_e}{m}N_Ae^{-E_g/kT}$
Where $m = 12.01115 g/mol$
mass of the Earth is $M_e = 5.98 \times 10^{24} kg.$
Number Avogadro = $ 6.02 \times 10^{23} /mol$
Substitute all the values into equation
$P = \frac{5.98 \times 10^{24} kg}{12.01115 g/mol}(6.02 \times 10^{23} /mol) (3 \times 10^{-93})$
$P = 9\times10^{-43} \approx 10^{-42}$
