Answer
$d_{av} = 0.23 nm$
Work Step by Step
To find the average distance, use the equation
$d_{avg} = n^{1/3}$
Take $n$ from (b) which is $8.43\times10^{28} m ^{-3}$
So
$d_{avg} = (8.43\times10^{28} m ^{-3})^{1/3}$
$d_{av} = 0.23 nm$