Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 41 - Conduction of Electricity in Solids - Problems - Page 1273: 11c

Answer

At E =7.00 eV, $N_0=9.01\times 10^{27} m^{-3}.eV^{-1}$

Work Step by Step

At E = 7.00 eV, $N_0 = \frac{6.81\times 10^{27} m^{-3}.eV^{-3/2}(7.00 eV)^{1/2} }{[e^{7.00 eV - 7.00eV/(8.62 \times 10^{-5} eV/K)(1000K)} + 1]}$ $N_0=9.01\times 10^{27} m^{-3}.eV^{-1}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.