Answer
$E_F = 7.00 MeV$
Work Step by Step
The equation to find Fermi Energy is
$E_F = \frac{(0.121)(hc^3)}{m_e c^{2}} n^{2/3}$
where
$hc = 1240 eV.nm$
$m_e c^2 = 511 \times 10^3 eV$
$n = 8.43 \times 10^{28} m^{-3}$
substitute into equation
$E_F = \frac{(0.121)(1240 eV.nm^3)}{(511 \times 10^3 eV)} (8.43 \times 10^{28} m^{-3})^{2/3}$
$E_F = 7.00 eV$
