Answer
$E = 3.55\times 10^4~eV$
Work Step by Step
We can find the energy of a photon with this wavelength:
$E = \frac{hc}{\lambda}$
$E = \frac{(6.63\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{35.0\times 10^{-12}~m}$
$E = 5.683\times 10^{-15}~J$
$E = (5.683\times 10^{-15}~J)(\frac{1~eV}{1.6\times 10^{-19}~J})$
$E = 3.55\times 10^4~eV$
