Answer
Energy is absorbed at a rate of $~~3.62\times 10^{-17}~W$
Work Step by Step
We can find the photon energy:
$E = \frac{hc}{\lambda}$
$E = \frac{(6.63\times 10^{-34}~J\cdot s)(3.0\times 10^8~m/s)}{550\times 10^{-9}~m}$
$E = 3.62\times 10^{-19}~J$
We can find the rate at which energy is absorbed:
$Power = (100~photons/s)(3.62\times 10^{-19}~J/photon) = 3.62\times 10^{-17}~W$
Energy is absorbed at a rate of $~~3.62\times 10^{-17}~W$