Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 38 - Photons and Matter Waves - Problems - Page 1182: 28b

Answer

$\lambda = 2.43\times 10^{-12}~m$

Work Step by Step

In part (a), we found that $p = 0.511~MeV/c$ We can find the wavelength: $p = \frac{h}{\lambda}$ $\lambda = \frac{h}{p}$ $\lambda = \frac{hc}{0.511~MeV}$ $\lambda = \frac{(6.63\times 10^{-34}~J\cdot s)(3.0\times 10^8~m/s)}{(0.511\times 10^6~eV)(1.6\times 10^{-19}~J/eV)}$ $\lambda = 2.43\times 10^{-12}~m$
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