Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 38 - Photons and Matter Waves - Problems - Page 1182: 27a

Answer

The wavelength is $~~2.73~pm$

Work Step by Step

We can find $\Delta \lambda$: $\Delta \lambda = \frac{h}{mc}~(1 - cos~\phi)$ $\Delta \lambda = \frac{6.63\times 10^{-34}~J~s}{(9.109\times 10^{-31}~kg)(3.0\times 10^8~m/s)}~(1 - cos~30^{\circ})$ $\Delta \lambda = 3.25\times 10^{-13}~m$ We can find the new wavelength: $\lambda_f = (2.40~pm)+(3.25\times 10^{-13}~m)$ $\lambda_f = 2.73~pm$ The wavelength is $~~2.73~pm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.