Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 38 - Photons and Matter Waves - Problems - Page 1182: 13

Answer

$4.6\times 10^{26}~photons~~$ are emitted.

Work Step by Step

We can find the total energy emitted in the form of photons during the bulb's lifetime: $E = (60~W)(0.93)(730~h)(3600~s/h) = 1.466424\times 10^8~J$ We can find the photon energy: $E = \frac{hc}{\lambda}$ $E = \frac{(6.63\times 10^{-34}~J\cdot s)(3.0\times 10^8~m/s)}{630\times 10^{-9}~m}$ $E = 3.157\times 10^{-19}~J$ We can find the total number $N$ of photons emitted: $N = \frac{1.466424\times 10^8~J}{3.157\times 10^{-19}~J/photon} = 4.6\times 10^{26}~photons$ $4.6\times 10^{26}~photons~~$ are emitted.
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