Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 477: 85b

Answer

The second longest wavelength is $~~120~cm$

Work Step by Step

We can find the possible wavelengths of the standing waves: $\lambda = \frac{2L}{n}$ $\lambda = \frac{2L}{1}, \frac{2L}{2}, \frac{2L}{3}, ...$ $\lambda = \frac{(2)(120~cm)}{1}, \frac{(2)(120~cm)}{2}, \frac{(2)(120~cm)}{3}, ...$ $\lambda = 240~cm, 120~cm, 80~cm, ...$ The second longest wavelength is $~~120~cm$
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