Answer
$f_2=96.0Hz$
Work Step by Step
We can find the frequency of the two loop standing wave as
$f_2=\frac{v}{\lambda_2}$
We plug in the known values to obtain:
$f_2=\frac{144}{1.5}=96.0Hz$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 16 - Waves-I - Problems - Page 477: 79e
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