Answer
$f_2=880Hz$
Work Step by Step
As we know that
$f_n=nf$ that is the higher frequencies are multiples of the lowest frequency
for frequency of second harmonic $n=2$
$f_2=2f$
We plug in the known values to obtain:
$f_2=2(440)=880Hz$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 16 - Waves-I - Problems - Page 477: 80a
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