Answer
$\lambda_{min}=1.0m$
$\lambda_{max}=2.0\times 10^2m$
Work Step by Step
We know that
$\lambda=\frac{c}{f}$
The minimum wavelength is given as
$\lambda_{min}=\frac{c}{f_{max}}$
We plug in the known values to obtain:
$\lambda_{min}=\frac{3.0\times 10^{8}}{300\times 10^{6}}=1.0m$
The maximum wavelength is given as
$\lambda_{max}=\frac{c}{f_{min}}$
$\lambda_{max}=\frac{3.0\times 10^{8}}{1.5\times 10^{6}}=1.0m=2.0\times 10^2m$
