Answer
$\pm0.50\;cm$
Work Step by Step
When,
$P=0$
Therefore,
$\cos(kx-\omega t)=0$
Thus,
$\sin(kx-\omega t)=\pm 1$
$\therefore$ When this minimum transfer occurs, the transverse displacement y becomes
$y=0.50\times (\pm 1)\;cm=\pm0.50\;cm$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 16 - Waves-I - Problems - Page 477: 71g
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