Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 474: 44b

Answer

$$26.4 \mathrm{Hz} $$

Work Step by Step

We know (wavelength of wave with low resonant frequency) $f_{1}$ is $$\lambda_{1}=2 L,$$ where $L =125 \mathrm{cm} .$ $\text{Thus,}$ $$ f_{1}=\frac{v}{\lambda_{1}}=\frac{66.1 \mathrm{m} / \mathrm{s}}{2(1.25 \mathrm{m})}=26.4 \mathrm{Hz} $$
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