Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 474: 43a

Answer

$f_1=7.91Hz$

Work Step by Step

We know that, $f=\frac{v}{\lambda}$ For possible wavelengths,, the formula is: $\lambda=\frac{2L}{n}$ This can be rearranged as: $f=\frac{nv}{2L}$ As $v=\sqrt\frac{T}{\mu}=\sqrt\frac{TL}{M}$, so $f_n=\frac{n}{2L}\sqrt\frac{TL}{M}=\frac{n}{2}\sqrt\frac{T}{LM}$ We plug in the known values to obtain: $f_n=\frac{n}{2}\sqrt\frac{250}{(10)(0.1)}=n(7.91)Hz$ The first lowest frequency is: $f_1=1(7.91)=7.91Hz$
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