Answer
The amplitude of the resultant wave is $~~3.29~mm$
Work Step by Step
We can find the horizontal component of the resultant wave's amplitude:
$y_{mh}' = (y_{m1}) cos ~(0) + (y_{m2}) cos~(0.80~\pi)$
$y_{mh}' = (4.60~mm) cos ~(0) + (5.60~mm) cos~(0.80~\pi)$
$y_{mh}' = 0.0695~mm$
We can find the vertical component of the resultant wave's amplitude:
$y_{mv}' = (y_{m1}) sin ~(0) + (y_{m2}) sin~(0.80~\pi)$
$y_{mv}' = (4.60~mm) sin ~(0) + (5.60~mm) sin~(0.80~\pi)$
$y_{mv}' = 3.29~mm$
We can find the amplitude of the resultant wave:
$y_m' = \sqrt{(0.0695~mm)^2+(3.29~mm)^2}$
$y_m' = 3.29~mm$
The amplitude of the resultant wave is $~~3.29~mm$
