Answer
$\omega = 1100~s^{-1}$
Work Step by Step
On the graph, we can see that $\lambda = 0.40~m$
We can find $k$:
$k = \frac{2\pi}{\lambda}$
$k = \frac{2\pi}{0.40~m}$
$k = 15.7~m^{-1}$
We can find the wave speed $v$:
$v = \frac{0.560~m}{0.0080~s}$
$v = 70~m/s$
We can find $\omega$:
$v = \frac{\omega}{k}$
$\omega = v~k$
$\omega = (70~m/s)(15.7~m^{-1})$
$\omega = 1100~s^{-1}$
