Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 474: 41b

Answer

$\lambda=16.8m$

Work Step by Step

We can find the longest possible wavelength as: $L=\frac{\lambda}{2}$ Rearranging the formula to find $\lambda$ and then substituting the value of $L$, we find that; $\lambda=2L=2(8.40)=16.8m$
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