Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 288: 27a

Answer

$a = 0.73~m/s^2$

Work Step by Step

We can express the angular speed in units of $rad/s$: $\omega = (33\frac{1}{3}~rev/min)(\frac{2\pi~rad}{1~rev})(\frac{1~min}{60~s}) = 3.49~rad/s$ We can find the centripetal acceleration: $a = \omega^2~r$ $a = (3.49~rad/s)^2~(0.060~m)$ $a = 0.73~m/s^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.