Answer
$$
\theta=600 \mathrm{rev}
$$
Work Step by Step
to solve this problem we can use the same values we used before in part $(c)$, Eq. $10-15$ becomes
$$
\theta=\frac{1}{2}\left(\omega_{0}+\omega\right) t=\frac{1}{2}(200 \mathrm{rev} / \min +1000 \mathrm{rev} / \min )(1.0 \mathrm{min})=600 \mathrm{rev}
$$
