Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 17 - Sections 17.1-17.9 - Exercises - Problems by Topic - Page 853: 44a

Answer

Low temperature.

Work Step by Step

Since the phase change of water is from gas to liquid, both $\Delta H$ and $\Delta S$ are negative. $\Delta G=\Delta H-T\Delta S $ is negative for a spontaneous process. Since $\Delta H$ and $\Delta S$ are negative, $\Delta H-T\Delta S\lt0 $ only for low temperatures.
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