Answer
$\Delta G^{\circ}_{rxn}=-2247\,kJ$
The reaction is spontaneous.
Work Step by Step
$\Delta G^{\circ}_{rxn}=\Delta H^{\circ}_{rxn}-T\Delta S^{\circ}_{rxn}$
$=-2217\,kJ-[(25+273.15)K](101.1\,J/K)$
$=(-2217\times10^{3}\,J)-(298.15\times101.1\,J)$
$=-2247\times10^{3}\,J=-2247\,kJ$
The reaction is spontaneous because $\Delta G^{\circ}_{rxn}$ is negative.
