Answer
$\Delta S_{univ}=396\,J/K$
The reaction is spontaneous.
Work Step by Step
For a spontaneous process, $\Delta S_{univ}$ is positive.
$\Delta S_{univ}=\Delta S_{sys}+\Delta S_{surr}$
$\Delta S_{surr}=\frac{-\Delta H_{sys}}{T}=\frac{-(-95\,kJ)}{398\,K}=\frac{95\times10^{3}\,J}{398\,K}=239\,J/K$
$\Delta S_{sys}=157\,J/K$
Therefore,
$\Delta S_{univ}=(157\,J/K)+(239\,J/K)=396\,J/K$
As $\Delta S_{univ}$ is positive, the reaction is spontaneous.
