Answer
$\Delta$S$_{sys}$ $\lt$ 0 because 3 moles of gas are being converted to 2 moles of gas. Given that $\Delta$H is greater than 0 and $\Delta$S$_{surr}$ is less than 0, the reaction is non-spontaneous at all temperatures.
Work Step by Step
$\Delta$S$_{sys}$ $\lt$ 0 because 3 moles of gas are being converted to 2 moles of gas. Given that $\Delta$H is greater than 0 and $\Delta$S$_{surr}$ is less than 0, the reaction is non-spontaneous at all temperatures.