Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 17 - Sections 17.1-17.9 - Exercises - Problems by Topic - Page 853: 35a

Answer

$1.29\times10^{3}\,J/K$

Work Step by Step

$\Delta S_{surr}=\frac{-\Delta H_{sys}}{T}=\frac{-\Delta H^{\circ}_{rxn}}{T}=\frac{-(-385\,kJ)}{298\,K}$ $=\frac{385\times10^{3}\,J}{298\,K}=1.29\times10^{3}\,J/K$
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