Answer
$1.29\times10^{3}\,J/K$
Work Step by Step
$\Delta S_{surr}=\frac{-\Delta H_{sys}}{T}=\frac{-\Delta H^{\circ}_{rxn}}{T}=\frac{-(-385\,kJ)}{298\,K}$
$=\frac{385\times10^{3}\,J}{298\,K}=1.29\times10^{3}\,J/K$
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