Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 17 - Sections 17.1-17.9 - Exercises - Problems by Topic - Page 853: 37a

Answer

$\Delta S_{univ}=-649\,J/K$, nonspontaneous.

Work Step by Step

For a spontaneous process, $\Delta S_{univ}$ is positive. $\Delta S_{univ}=\Delta S_{sys}+\Delta S_{surr}$ $\Delta S_{surr}=\frac{-\Delta H_{sys}}{T}=\frac{-(115\,kJ)}{298\,K}=\frac{-115\times10^{3}\,J}{298\,K}=-386\,J/K$ $\Delta S_{sys}=-263\,J/K$ Therefore, $\Delta S_{univ}=(-263\,J/K)+(-386\,J/K)=-649\,J/K$ As $\Delta S_{univ}$ is negative, the reaction is nonspontaneous.
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