Answer
316 K
Work Step by Step
$\Delta S_{surr}=\frac{-\Delta H_{sys}}{T}\implies T=\frac{-\Delta H_{sys}}{\Delta S_{surr}}$
Given that $\Delta S_{surr}=\Delta S^{\circ}_{rxn}=354\,J/K$ and
$\Delta H^{\circ}_{rxn}=-112\,kJ$
Then, $T=\frac{-(-112\,kJ)}{354\,J/K}=\frac{112\times10^{3}\,J}{354\,J/K}=316\,K$
