Answer
$5.00\times10^{3}\,J/K$
Work Step by Step
$\Delta S_{surr}=\frac{-\Delta H_{sys}}{T}=\frac{-\Delta H^{\circ}_{rxn}}{T}=\frac{-(-385\,kJ)}{77\,K}$
$=\frac{385\times10^{3}\,J}{77\,K}=5.00\times10^{3}\,J/K$
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 17 - Sections 17.1-17.9 - Exercises - Problems by Topic - Page 853: 35b
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