Answer
$$K_P = 18$$
Work Step by Step
1. Write the equilibrium constant expression:
- The exponent of each concentration is equal to its balance coefficient.
$$K_P = \frac{[Products]}{[Reactants]} = \frac{P_{ B } ^{ 2 }}{P_{ A }}$$
2. At equilibrium, these are the concentrations of each compound:
$ P_{ A } = 1.32 - x$
$ P_{ B } = 0 + 2x$
- We know that, at equilibrium, $P_A = 0.25$, thus:
$0.25 = 1.32 -x$
$x = 1.07$
$P_B = 2(1.07) = 2.14$
$$K_P = \frac{2.14^2}{0.25} = 18$$
