Answer
$$P_{NOBr} = 0.308 \space atm = 234 \space torr$$
Work Step by Step
- Convert all the pressures to atm: 1 atm = 760 torr.
$P_{NO} = 0.142 \space atm$
$P_{Br_2} = 0.166 \space atm$
1. Write the equilibrium constant expression:
- The exponent of each concentration is equal to its balance coefficient.
$$K_P = \frac{[Products]}{[Reactants]} = \frac{P_{ NOBr } ^{ 2 }}{P_{ NO } ^{ 2 }P_{ Br_2 }}$$
2. Solve for the missing concentration:
$$ \sqrt[2]{K_P \times P_{ NO } ^{ 2 }P_{ Br_2 }}{} = P_{NOBr}$$
3. Evaluate the expression:
$$ P_{NOBr} = \sqrt[2]{(28.4) \times {( 0.142 )^{ 2 }( 0.166 )}{}}$$
$$P_{NOBr} = 0.308 \space atm = 234 \space torr$$
