Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 14 - Sections 14.1-14.9 - Exercises - Problems by Topic - Page 690: 35

Answer

136

Work Step by Step

$K_{c}= \frac{[CH_{3}OH]}{[CO][H_{2}]^{2}} = \frac{0.185}{0.105(0.114^{2})} \approx 136$
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