Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 14 - Sections 14.1-14.9 - Exercises - Problems by Topic - Page 690: 36

Answer

0.0987

Work Step by Step

$K_{c}$=$ [NH_{3}][H_{2}S]$ = 0.278×0.355 = 0.0987 ($[NH_{4}HS]$ do not appear in the equilibrium expression as it is a pure solid.)
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