Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 14 - Sections 14.1-14.9 - Exercises - Problems by Topic - Page 690: 33a

Answer

$$K_c = \frac{[HC{O_3}^-][OH^-]}{[C{O_3}^{2-}]}$$

Work Step by Step

$$K_c = \frac{[Products]}{[Reactants]} = \frac{[HC{O_3}^-][OH^-]}{[C{O_3}^{2-}]}$$ - The equilibrium expression for a chemical equation is equal to the multiplication of the concentration of the products divided by that of the reactants. Notice: The equilibrium coefficients of each molecule/ion will give the exponent. In that case, since all the coefficients are equal to 1, all the exponents are also equal to 1. That expression does not include compounds in the solid or liquid state. In this case, $H_2O(l)$ was not included for that specific reason.
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