Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Cumulative Problems - Page 41: 131

Answer

The maximum fraction of the air in the room that could be displaced by the gaseous nitrogen is equal to $0.492$

Work Step by Step

1. When the liquid nitrogen vaporizes, its volume changes, but the mass still constant. Calculate the total mass in 175 L of $liquid$ nitrogen. $$175 \space L \times \frac{0.808 \space g}{1 \space mL} \times \frac{1000 \space mL}{1 \space L} = 141400 \space g$$ 2. The fraction of the air in the room that could be displaced by the gaseous nitrogen is: $$\frac{Volume \space of \space gaseous \space nitrogen }{Total \space volume \space of \space the \space room}$$ Volume ($N_2$): $$141400 \space g \times \frac{1 \space L}{1.15 \space g} = 122956.5$$ Volume (room): $$V_{room} = 10.00 \space m \times 10.00 \space m \times 2.50 \space m = 250 \space m^3 \times \frac{1000 \space L}{1 \space m^3}$$ $$V_{room} = 250000 \space L$$ Thus, the fraction is equal to: $$\frac{122956.5}{250000} = 0.492$$ (3 significant figures)
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