Answer
$4.06 \times 10^{14}g/cm^{3}$
Work Step by Step
1. Calculate the volume of the proton by using the formula of the volume of a sphere
$V=\frac{4\times r^{3} \times \pi}{3} = \frac{4\times (1 \times 10^{-13} cm)^{3} \times \pi}{3} = 4.19 \times 10^{-39} cm^{3}$
2. Calculate the density of the proton
$p=\frac{m}{V}=\frac{1.7 \times 10^{-24}g}{4.19 \times 10^{-39} cm^{3}}=4.06 \times 10^{14}g/cm^{3} $
