Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Cumulative Problems - Page 41: 119

Answer

$311827$ $lb$

Work Step by Step

1. Convert $kg/m^{3}$ to $lb/yd^{3}$ using conversion factors: $1m^{3}= 1.30795yd^{3}$ and $1kg = 2.20462 lb$. The density of water is $1000kg/m^{3}$. $p = \frac{1000kg/m^{3} \times 2.20462 lb/kg }{1.30795yd^{3}/ m ^{3}} = 1685.55 lb/yd^{3}$ 2. Calculate the mass using density and volume: $m = p \times V = 1685.55 lb/yd^{3} \times 185yd^{3} = 311827 lb$
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