Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.4 Equations Involving Inverse Trigonometric Functions - 6.4 Exercises - Page 280: 35

Answer

$x = 0$

Work Step by Step

$sin^{-1}~x-tan^{-1}~1 = -\frac{\pi}{4}$ $sin^{-1}~x-\frac{\pi}{4} = -\frac{\pi}{4}$ $sin^{-1}~x = 0$ $x = sin~0$ $x = 0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.