Answer
$1$
Work Step by Step
Given: $4\pi+4tan^{-1}(x)=\pi$
$4tan^{-1}(x)=-3 \pi$
$tan^{-1}(x)=(-\frac{3 \pi}{4})$ (Divide by 4)
$x=tan(-\frac{3 \pi}{4})$
Apply definition of arctangent.
$x=1$
Hence, $x=1$
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