Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.4 Equations Involving Inverse Trigonometric Functions - 6.4 Exercises - Page 280: 28

Answer

$1$

Work Step by Step

Given: $4\pi+4tan^{-1}(x)=\pi$ $4tan^{-1}(x)=-3 \pi$ $tan^{-1}(x)=(-\frac{3 \pi}{4})$ (Divide by 4) $x=tan(-\frac{3 \pi}{4})$ Apply definition of arctangent. $x=1$ Hence, $x=1$
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