Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.4 Equations Involving Inverse Trigonometric Functions - 6.4 Exercises - Page 280: 29

Answer

$\pi-3$

Work Step by Step

Given: $2arccos(\frac{y-\pi}{3})=2\pi$ $arccos(\frac{y-\pi}{3})=\pi$ $(\frac{y-\pi}{3})=cos(\pi)$ $(\frac{y-\pi}{3})=-1$ $({y-\pi})=-3$ Hence, $y=\pi-3$
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