Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.4 Equations Involving Inverse Trigonometric Functions - 6.4 Exercises - Page 280: 20

Answer

$x=arccos(\frac{y-4}{3})$

Work Step by Step

$y=4+3cosx$ $y-4=3cosx$ Divide both sides by 3. $cosx=\frac{y-4}{3}$ Apply definition of arccos. $x=arccos(\frac{y-4}{3})$ Hence, $x=arccos(\frac{y-4}{3})$
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