Answer
$\cot$$^{2}$ 135$^{\circ}$ + $\tan$$^{4}$ 60$^{\circ}$ - $\sin$$^{4}$ 180$^{\circ}$ = 10
Work Step by Step
$\cot$$^{2}$ 135$^{\circ}$ + $\tan$$^{4}$ 60$^{\circ}$ - $\sin$$^{4}$ 180$^{\circ}$
$\cot$ 135$^{\circ}$ = -1
$\tan$ 60$^{\circ}$ = $\sqrt3$
$\sin$ 180$^{\circ}$ = 0
= (-1)$^{2}$ + ($\sqrt3$)$^{4}$ - (0)$^{4}$
= 1 + 9 + 0
= 10
Therefore:
$\cot$$^{2}$ 135$^{\circ}$ + $\tan$$^{4}$ 60$^{\circ}$ - $\sin$$^{4}$ 180$^{\circ}$ = 10
