Answer
$\sin$(-390) = -$\frac{1}{2}$
$\cos$(-390) = $\frac{\sqrt3}{2}$
$\tan$(-390) = -$\frac{\sqrt3}{3}$
$\cot$(-390) = -$\sqrt3$
$\csc$(-390) = -2
$\sec$(-390) = $\frac{2\sqrt3}{3}$
Work Step by Step
-390$^{\circ}$
We must first fine the coterminal angle:
-390$^{\circ}$ + 360$^{\circ}$ = -30$^{\circ}$
-30 is in Quadrant IV. Therefore all the trigonometric functions are negative with the exception of $\cos$ and $\sec$
$\sin$(-30) = -$\frac{1}{2}$
$\cos$(-30) = $\frac{\sqrt3}{2}$
$\tan$(-30) = -$\frac{\sqrt3}{3}$
$\cot$(-30) = -$\sqrt3$
$\csc$(-30) = -2
$\sec$(-30) = $\frac{2\sqrt3}{3}$
