Answer
$sin$(-300)$^{\circ}$ = $\frac{\sqrt3}{2}$
$cos$(-300)$^{\circ}$ = $\frac{1}{2}$
$tan$(-300)$^{\circ}$ = $\sqrt3$
$cot$(-300)$^{\circ}$ = $\frac{\sqrt3}{3}$
$csc$(-300)$^{\circ}$ = $\frac{2\sqrt3}{3}$
$sec$(-300)$^{\circ}$ = 2
Work Step by Step
-300$^{\circ}$
We can solve for the functions by using the coterminal angle. We can find the coterminal angle by adding or subtracting 360$^{\circ}$ as many times as needed.
-300$^{\circ}$ + 360$^{\circ}$ = 60$^{\circ}$
$sin$(60)$^{\circ}$ = $\frac{\sqrt3}{2}$
$cos$(60)$^{\circ}$ = $\frac{1}{2}$
$tan$(60)$^{\circ}$ = $\frac{\sqrt3}{1}$ = $\sqrt3$
$cot$(60)$^{\circ}$ = $\frac{1}{\sqrt3}$ = $\frac{\sqrt3}{3}$
$csc$(60)$^{\circ}$ = $\frac{2}{\sqrt3}$ = $\frac{2\sqrt3}{3}$
$sec$(60)$^{\circ}$ = $\frac{2}{1}$ = 2
