Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 62: 46

Answer

$\sin$$^{2}$ 225$^{\circ}$ + $\cos$$^{2}$ 225$^{\circ}$ = 1

Work Step by Step

$\sin$$^{2}$ 225$^{\circ}$ + $\cos$$^{2}$ 225$^{\circ}$ $\sin$ 225$^{\circ}$ = -$\sin$ 45 = $\frac{-\sqrt2}{2}$ $\cos$ 225$^{\circ}$ = -$\cos$ 45 = -$\frac{-\sqrt2}{2}$ Therefore: = ($\frac{-\sqrt2}{2}$)$^{2}$ + ($\frac{-\sqrt2}{2}$)$^{2}$ = ($\frac{2}{4}$) + ($\frac{2}{4}$) = 1 $\sin$$^{2}$ 225$^{\circ}$ + $\cos$$^{2}$ 225$^{\circ}$ = 1
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