Answer
$sin$(405)$^{\circ}$ = $\frac{\sqrt2}{2}$
$cos$(405)$^{\circ}$ = $\frac{\sqrt2}{2}$
$tan$(405)$^{\circ}$ = 1
$cot$(405)$^{\circ}$ = 1
$sec$(405)$^{\circ}$ = $\sqrt2$
$sin$(405)$^{\circ}$ = $\sqrt2$
Work Step by Step
405$^{\circ}$
We can solve for the functions by using the coterminal angle. We can find the coterminal angle by adding or subtracting 360$^{\circ}$ as many times as needed.
405$^{\circ}$ - 360$^{\circ}$ = 45$^{\circ}$
$sin$(45)$^{\circ}$ = $\frac{1}{\sqrt2}$ = $\frac{\sqrt2}{2}$
$cos$(45)$^{\circ}$ = $\frac{1}{\sqrt2}$ = $\frac{\sqrt2}{2}$
$tan$(45)$^{\circ}$ = $\frac{1}{1}$ = 1
$cot$(45)$^{\circ}$ = $\frac{1}{1}$ = 1
$sec$(45)$^{\circ}$ = $\frac{\sqrt2}{1}$ = $\sqrt2$
$sin$(45)$^{\circ}$ = $\frac{\sqrt2}{1}$ = $\sqrt2$
