Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Acute Angles and Right Triangles - Section 2.2 Trigonometric Functions of Non-Acute Angles - 2.2 Exercises - Page 62: 16

Answer

$\sin$ 30$^{\circ}$ = $\frac{1}{2}$ $\tan$ 30$^{\circ}$ = -$\frac{\sqrt3}{3}$ $\sec$ 30$^{\circ}$ = -$\frac{2\sqrt3}{3}$

Work Step by Step

We use the reference angle to determine the trigonometric functions. $\theta$$^{1}$ = 180$^{\circ}$ - 150$^{\circ}$ $\theta$$^{1}$ = 30$^{\circ}$ $\sin$ 30$^{\circ}$ = $\frac{1}{2}$ $\tan$ 30$^{\circ}$ = $\frac{1}{-\sqrt3}$ = -$\frac{\sqrt3}{3}$ $\sec$ 30$^{\circ}$ = $\frac{2}{-\sqrt3}$ = -$\frac{2\sqrt3}{3}$
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